要求
删除链表中的重复元素,例如1->1->1->2->3->3->4->4->5,返回2->5
代码实现
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| #include <iostream>
using namespace std;
struct ListNode {
int val;
ListNode *next;
ListNode(int x) : val(x), next(NULL) {}
};
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if (head==NULL||head->next==NULL) {
return head;
}else{
ListNode* newHead = new ListNode(0);
newHead->next = head;
ListNode* pre = newHead;
ListNode* p = pre->next;
ListNode* next = NULL;
while (p!=NULL&&p->next!=NULL) {
next = p->next;
if (p->val==next->val) {
while (next!=NULL&&next->val==p->val) {
next = next->next;
}
pre->next = next;
p = next;
}else{
pre = pre->next;
p = p->next;
}
}
return newHead->next;
}
}
};
int main(int argc, const char * argv[]) {
return 0;
}
|